On 27/03/2013 06:42, Νίκος Γκρ33κ wrote:
Τη Τετάρτη, 27 Μαρτίου 2013 6:26:06 π.μ. UTC+2, ο χρήστης ru...@yahoo.com
έγραψε:
If not, maybe you can try adding a print statement to your code that
will print the value of 'page'. This will be easier to do if you
can run you code interactively. If you have to run it via a webserver
than maybe you'll need wrap the print output in html commands to make
it visible on the page, or to write it to a file.
I tried what you suggested by doign the following:
print( page )
sys.exit(0)
cur.execute( '''SELECT hits FROM counters WHERE url = %s''', (page,) )
and the result is printed in the webpage as 'index.html'
so page seem s to be a string but the error is still persistant.
Anything else i need to try?
A brief look at the documentation tells me that MySQL uses '?' as the
placeholder instead of '%s':
cur.execute('''SELECT hits FROM counters WHERE url = ?''', (page, ))
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