Wolfgang Maier wrote:
> Chris Angelico <rosuav <at> gmail.com> writes:
>
>>
>> Try printing out this expression:
>>
>> "%.2f"%value if value else ''
>>
>> Without the rest of your code I can't tell you how to plug that in,
>> but a ternary expression is a good fit here.
>>
>> ChrisA
>>
>
> Unfortunately, that's not working, but gives a TypeError: a float is
> required when the first value evaluates to False.
> Apparently it's not that easy to combine number formatting with logical
> operators - the same happens with my idea ('{:.2f}').format(value or '').
Here's a round-about way:
class Prepare:
def __init__(self, value):
self.value = value
def __format__(self, spec):
if self.value is None or self.value == 0:
return format(0.0, spec).replace(".", " ").replace("0", " ")
elif isinstance(self.value, str):
return self.value.rjust(len(format(0.0, spec)))
return format(self.value, spec)
def prepare(row):
return map(Prepare, row)
data = [
("Credit", "Debit", "Description"),
(100, 0, "Initial balance"),
(123.45, None, "Payment for cabbages"),
(0.0, 202.0, "Telephone bill"),
]
for row in data:
print("{:10.2f} {:10.2f} {}".format(*prepare(row)))
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