On 19/02/13 00:18, Steven D'Aprano wrote: > Terry Reedy wrote: > >> On 2/18/2013 6:47 AM, John Reid wrote: >> >>> I was hoping namedtuples could be used as replacements for tuples >> > in all instances. >> >> This is a mistake in the following two senses. First, tuple is a class >> with instances while namedtuple is a class factory that produces >> classes. (One could think of namedtuple as a metaclass, but it was not >> implemented that way.) > > > I think you have misunderstood. I don't believe that John wants to use the > namedtuple factory instead of tuple. He wants to use a namedtuple type > instead of tuple. > > That is, given: > > Point3D = namedtuple('Point3D', 'x y z') > > he wants to use a Point3D instead of a tuple. Since: > > issubclass(Point3D, tuple) > > holds true, the Liskov Substitution Principle (LSP) tells us that anything > that is true for a tuple should also be true for a Point3D. That is, given > that instance x might be either a builtin tuple or a Point3D, all of the > following hold: > > - isinstance(x, tuple) returns True > - len(x) returns the length of x > - hash(x) returns the hash of x > - x[i] returns item i of x, or raises IndexError > - del x[i] raises TypeError > - x + a_tuple returns a new tuple > - x.count(y) returns the number of items equal to y > > etc. Basically, any code expecting a tuple should continue to work if you > pass it a Point3D instead (or any other namedtuple). > > There is one conspicuous exception to this: the constructor: > > type(x)(args) > > behaves differently depending on whether x is a builtin tuple, or a Point3D. >
Exactly and thank you Steven for explaining it much more clearly. -- http://mail.python.org/mailman/listinfo/python-list