On Jan 23, 11:33 pm, moonhk <moon...@gmail.com> wrote:
> Works.
>
> prndev = line.split()
> # print line
> for key in prndev :
> if key in 'lpr':
> val = prndev[5].replace("-P","")
> if val not in printque:
> printque[val] = 1
> else:
> printque[val] = printque[val] + 1
> if key in "/dev/null":
> val='null'
> if val not in printque:
> printque[val] = 1
> else:
> printque[val] = printque[val] + 1
>
> On Wed, Jan 23, 2013 at 6:12 PM, Oscar Benjamin
>
>
>
>
>
>
>
>
>
> <oscar.j.benja...@gmail.com> wrote:
> > On 23 January 2013 07:26, moonhkt <moon...@gmail.com> wrote:
> >> Hi Al
>
> >> I have Data file have below
>
> >> Data file
> >> V1
> >> V2
> >> V3
> >> V4
> >> V4
> >> V3
>
> >> How to using count number of data ?
>
> >> Output
> >> V1 = 1
> >> V2 = 1
> >> V3 =2
> >> V4 = 2
>
> >> # Global Veriable
> >> printque = {}
> >> in def have below
>
> >> printque[val] = printque[val] + 1
>
> >> I have below error
> >> File "xprintlogchk.py", line 78, in chklog
> >> printque[val] = printque[val] + 1
> >> KeyError: 'nan'
>
> > You can't retrieve the value of printque[val] if you haven't yet added
> > an entry with the key val to the dict. Try this:
>
> > if val not in printque:
> > printque[val] = 1
> > else:
> > printque[val] = printque[val] + 1
>
> > Oscar
>
> --
> moonhkt
> GMT+8
Tried below works
a = "A B"
karry = a.split()
age[karry[0]] = age.get(karry[0], 100) + 1
age[karry[1]] = age.get(karry[1], 0) + 1
age[karry[1]] = age.get(karry[1], 0) + 1
Result
A 101
B 2
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