On 18/01/13 02:02, Utpal Sarkar wrote:
Hi,I was assuming that sys.stdout would be referencing the same physical stream as iostreams::cout running in the same process, but this doesn't seem to be the case. The following code, which makes a call to a C++ function with a python wrapper called "write", that writes to cout: from cStringIO import StringIO import sys orig_stdout = sys.stdout sys.stdout = stringout = StringIO() write("cout") # wrapped C++ function that writes to cout print "-" * 40 print "stdout" sys.stdout = orig_stdout print stringout.getvalue() immediately writes "cout" to the console, then the separator "---...", and finally, as the return value of stringout.getvalue(), the string "stdout". My intention was to capture in stringout also the string written to cout from C++. Does anyone know what is going on, and if so, how I can capture what is written to cout in a python string? Thanks in advance.
You might have a better luck if you check std::ios::rdbuf (http://www.cplusplus.com/reference/ios/ios/rdbuf/)
Using std::ios::rdbuf() you can get the cout's streambuf, which is a filebuf for the stdout and then use std::ios::rdbuf(streambuf*) to replace cout's internal streambuf and replace it with your own implementation that captures everything written using cout before passing it back to the original streambuf.
This is essentially similar to assigning to sys.stdout in python. -- http://mail.python.org/mailman/listinfo/python-list
