On 01/13/2013 07:45 AM, subhabangal...@gmail.com wrote:
Dear Group,
I have a list like,
list1=[1,2,3,4,5,6,7,8,9,10,11,12]
Now, if I want to take a slice of it, I can.
It may be done in,
list2=list1[:3]
print list2
[1, 2, 3]
If I want to iterate the list, I may do as,
for i in list1:
print "Iterated Value Is:",i
Iterated Value Is: 1
Iterated Value Is: 2
Iterated Value Is: 3
Iterated Value Is: 4
Iterated Value Is: 5
Iterated Value Is: 6
Iterated Value Is: 7
Iterated Value Is: 8
Iterated Value Is: 9
Iterated Value Is: 10
Iterated Value Is: 11
Iterated Value Is: 12
Now, I want to combine iterator with a slicing condition like
for i=list2 in list1:
print "Iterated Value Is:",i
So, that I get the list in the slices like,
[1,2,3]
[4,5,6]
[7,8,9]
[10,11,12]
But if I do this I get a Syntax Error, is there a solution?
If anyone of the learned members may kindly let me know?
Apology for any indentation error,etc.
Thanking You in Advance,
Regards,
Subhabrata
Another good answer is to use a recipe from itertools docs page.
There are a lot of good recipes there and you may want to keep
them all in a module you can import from when needed. Here
is the recipe:
def grouper(n, iterable, fillvalue=None):
"""From itertools recipes: collect data into fixed-length chunks or
blocks."""
# grouper(3, 'ABCDEFG', 'x') --> ABC DEF Gxx
args = [iter(iterable)] * n
return zip_longest(fillvalue=fillvalue, *args)
>>> list(grouper(3, range(12))
...
...
...
... )
[(0, 1, 2), (3, 4, 5), (6, 7, 8), (9, 10, 11)]
HTH, - mitya
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