On Monday, December 24, 2012 7:12:43 PM UTC+1, Joshua Landau wrote:
> On 24 December 2012 16:18, Roy Smith <r...@panix.com> wrote:
>
>
>
>
> In article <40d108ec-b019-4829-a969-c8ef51386...@googlegroups.com>,
>
> Pander Musubi <pander...@gmail.com> wrote:
>
>
>
> > Hi all,
>
>
> >
>
> > I would like to sort according to this order:
>
> >
>
> > (' ', '.', '\'', '-', '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a',
>
> > 'A', '?', '?', '?', '?', '?', '?', '?', '?', '?', '?', 'b', 'B', 'c', 'C',
>
> > '?', '?', 'd', 'D', 'e', 'E', '?', '?', '?', '?', '?', '?', '?', '?', 'f',
>
> > 'F', 'g', 'G', 'h', 'H', 'i', 'I', '?', '?', '?', '?', '?', '?', '?', '?',
>
> > 'j', 'J', 'k', 'K', 'l', 'L', 'm', 'M', 'n', '?', 'N', '?', 'o', 'O', '?',
>
> > '?', '?', '?', '?', '?', '?', '?', '?', '?', 'p', 'P', 'q', 'Q', 'r', 'R',
>
> > 's', 'S', 't', 'T', 'u', 'U', '?', '?', '?', '?', '?', '?', '?', '?', 'v',
>
>
> > 'V', 'w', 'W', 'x', 'X', 'y', 'Y', 'z', 'Z')
>
> >
>
>
> > How can I do this? The default sorted() does not give the desired result.
>
>
>
> <snip>
>
>
>
>
> Given all that, I would start by writing some code which turned your
>
> alphabet into a pair of dicts. One maps from the code point to a
>
> collating sequence number (i.e. ordinals), the other maps back.
>
> Something like (for python 2.7):
>
>
>
> alphabet = (' ', '.', '\'', '-', '0', '1', '2', '3', '4', '5',
>
> '6', '7', '8', '9', 'a', 'A', '?', '?', '?', '?',
>
> [...]
>
>
> 'v', 'V', 'w', 'W', 'x', 'X', 'y', 'Y', 'z', 'Z')
>
>
>
> map1 = {c: n for n, c in enumerate(alphabet)}
>
> map2 = {n: c for n, c in enumerate(alphabet)}
>
>
>
> Next, I would write some functions which encode your strings as lists of
>
> ordinals (and back again)
>
>
>
> def encode(s):
>
> "encode('foo') ==> [34, 19, 19]" # made-up ordinals
>
> return [map1[c] for c in s]
>
>
>
> def decode(l):
>
> "decode([34, 19, 19]) ==> 'foo'"
>
> return ''.join(map2[i] for i in l)
>
>
>
> Use these to convert your strings to lists of ints which will sort as
>
> per your specified collating order, and then back again:
>
>
>
> encoded_strings = [encode(s) for s in original_list]
>
> encoded_strings.sort()
>
> sorted_strings = [decode(l) for l in encoded_strings]
>
>
>
> This isn't needed and the not-so-new way to do this is through .sort's key
> attribute.
>
>
>
>
> encoded_strings = [encode(s) for s in original_list]
> encoded_strings.sort()
> sorted_strings = [decode(l) for l in encoded_strings]
>
>
>
> changes to
>
>
>
>
> encoded_strings.sort(key=encode)
>
>
>
> [Which happens to be faster </reasonable_guess>]
>
>
>
>
> Hence you neither need map2 or decode:
>
>
> ## CODE ##
>
>
>
>
>
> alphabet = (
> ' ', '.', '\'', '-', '0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
> 'a', 'A', 'ä', 'Ä', 'á', 'Á', 'â', 'Â',
>
>
> 'à', 'À', 'å', 'Å', 'b', 'B', 'c', 'C', 'ç', 'Ç', 'd', 'D', 'e', 'E',
> 'ë', 'Ë', 'é', 'É', 'ê', 'Ê', 'è', 'È',
>
>
> 'f', 'F', 'g', 'G', 'h', 'H', 'i', 'I', 'ï', 'Ï', 'í', 'Í', 'î', 'Î',
> 'ì', 'Ì', 'j', 'J', 'k', 'K', 'l', 'L',
>
>
> 'm', 'M', 'n', 'ñ', 'N', 'Ñ', 'o', 'O', 'ö', 'Ö', 'ó', 'Ó', 'ô', 'Ô',
> 'ò', 'Ò', 'ø', 'Ø', 'p', 'P', 'q', 'Q',
>
>
> 'r', 'R', 's', 'S', 't', 'T', 'u', 'U', 'ü', 'Ü', 'ú', 'Ú', 'û', 'Û',
> 'ù', 'Ù', 'v', 'V', 'w', 'W', 'x', 'X',
>
>
> 'y', 'Y', 'z', 'Z'
> )
>
>
>
> hashindex = {character:index for index, character in enumerate(alphabet)}
>
> def string2sortlist(string):
> return [hashindex[s] for s in string]
>
>
>
>
> # Quickly make some stuff to sort. Let's try 200k, as that's what's suggested.
> import random
> things_to_sort = ["".join(random.sample(alphabet, random.randint(4, 6))) for
> _ in range(200000)]
>
>
>
>
> print(things_to_sort[:15])
>
>
> things_to_sort.sort(key=string2sortlist)
>
>
>
>
> print(things_to_sort[:15])
>
>
> ## END CODE ##
>
>
>
>
> Not-so-coincidentally, this is exactly the same as Ian Kelly's extension to
> Tomas Bach's method.
With Python2.7 I had to use
alphabet = (
u' ', u'.', u'\'', u'-', u'0', u'1', u'2', u'3', u'4', u'5', u'6', u'7', u'8',
u'9', u'a', u'A', u'ä', u'Ä', u'á', u'Á', u'â', u'Â',
u'à', u'À', u'å', u'Å', u'b', u'B', u'c', u'C', u'ç', u'Ç', u'd', u'D', u'e',
u'E', u'ë', u'Ë', u'é', u'É', u'ê', u'Ê', u'è', u'È',
u'f', u'F', u'g', u'G', u'h', u'H', u'i', u'I', u'ï', u'Ï', u'í', u'Í', u'î',
u'Î', u'ì', u'Ì', u'j', u'J', u'k', u'K', u'l', u'L',
u'm', u'M', u'n', u'ñ', u'N', u'Ñ', u'o', u'O', u'ö', u'Ö', u'ó', u'Ó', u'ô',
u'Ô', u'ò', u'Ò', u'ø', u'Ø', u'p', u'P', u'q', u'Q',
u'r', u'R', u's', u'S', u't', u'T', u'u', u'U', u'ü', u'Ü', u'ú', u'Ú', u'û',
u'Û', u'ù', u'Ù', u'v', u'V', u'w', u'W', u'x', u'X',
u'y', u'Y', u'z', u'Z'
)
to prevent
Traceback (most recent call last):
File "./sort.py", line 23, in <module>
things_to_sort.sort(key=string2sortlist)
File "./sort.py", line 15, in string2sortlist
return [hashindex[s] for s in string]
KeyError: '\xc3'
Thanks very much for this efficient code.
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