On 2012-12-10 01:19, Dave Angel wrote:
On 12/09/2012 07:52 PM, Victor Hooi wrote:
Hi,
I'm getting a strange error when I try to run the following:
for root, dirs, files in os.walk('./'):
for file in files:
if file.startswith('ml') and file.endswith('.xml') and 'entity' not
in file:
print(root)
print(file)
with open(os.path.join(root, file), 'r') as f:
print(f.name)
try:
tree = etree.parse(f)
root = tree.getroot()
print(f.name)
print(root.tag)
except xml.parsers.expat.ExpatError as e:
print('Unable to parse file {0} - {1}'.format(f.name,
e.message))
Where's the printout of the root and file variables? You're asking
os.path.join to work on them, and it's clearly upset about their types.
I see print statements, so you clearly were thinking along these lines.
But you don't show them. BTW, I'd be using print(repr(root)) and
print(repr(file)) instead, so you get a better idea of their type and value.
My guess for the problem is that you're trashing 'root' with the
contents of your try block. Try using a different name for the xml stuff.
The error is:
Traceback (most recent call last):
File "foo.py", line 275, in <module>
marketlink_configfiles()
File "foo.py", line 83, in bar
with open(os.path.join(root, file), 'r') as f:
File "C:\Python27\lib\ntpath.py", line 97, in join
if path[-1] in "/\\":
TypeError: 'in <string>' requires string as left operand, not Element
Cheers,
Victor
Incidentally, 'file' is a builtin type, so it's probably not a good idea
to hide it by using it as your own local variable.
It looks like Python 3 to me, which doesn't define 'file'.
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