Thanks to everyone for all the help! After careful consideration I decided to go with os.startfile(url)
It works just great! Here's my program in case anyone's interested. 5 points if you can guess what it does ;-) """Take a filepath from stdin and translate to the corresponding url and open up browser and show it.""" import sys import os myhtmlroot='C:\\Documents and Settings\\Gregory\\My Documents\\blendedtechnologies\\trunk' htmlroot='http://www.blendedtechnologies.com' filepath=sys.argv[1] filename=os.path.basename(filepath) filedir=os.path.dirname(filepath).replace(myhtmlroot,'').replace('\\','/') url=htmlroot+'/'+filedir+'/'+filename os.startfile(url) -Greg On 23 Jun 2005 10:04:32 -0700, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote: > If firefox is not your default browser, > os.system(r'"cd c:\Program Files\Mozilla Firefox & firefox "' + > '"www.blendertechnologies.com "') > > works for me. > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list
