On 20/11/2012 23:41, Tom Borkin wrote:
> Using shlex, I now have this:
> #!\Python27\python
> import os, subprocess
> path = os.path.join("C:\\", "Program Files", "Apache Group", "Apache2",
> "htdocs", "ccc", "run_alert.py")
> #subprocess.call(['SchTasks', '/Create', '/SC', 'ONCE', '/TN', '"test"',
> '/TR', path, '/ST', '23:50'])
> subprocess.call(['SchTasks', '/Create', '/SC', 'ONCE', '/TN', '"test"',
> '/TR', 'run_alert.py', '/ST', '23:50'])
> Both of the above commands throw the same error:
> ERROR: The filename, directory name or volume label syntax is incorrect.The following works for me: import subprocess path = r"C:\Program Files\Apache Group\Apache2\htdocs\ccc\run_alert.py" subprocess.call([ 'SchTasks', '/Create', '/SC', 'ONCE', '/TN', 'test', '/TR', path, '/ST', '23:50' ]) Things to note: * I haven't added extra quoting to any of the items in the command list which is subprocess.call's first parameter. The point about using the list (as opposed to passing an entire string which you can also do) is that the subprocess module can quote things as needed. If you've already added quotes, you'll get double-quoting which you almost certainly don't want. * (Obviously) I've formatted the subprocess.call as I have for clarity, especially via email. It's just a list. TJG -- http://mail.python.org/mailman/listinfo/python-list
