Le mercredi 31 octobre 2012 16:17:19 UTC+1, djc a écrit :
> I learn lots of useful things from the list, some not always welcome. No
>
> sooner had I found a solution to a minor inconvenience in my code, than
>
> a recent thread here drew my attention to the fact that it will not work
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> for python 3. So suggestions please:
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>
>
> TODO 2012-10-22: sort order numbers first then alphanumeric
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> >>> n
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> ('1', '10', '101', '3', '40', '31', '13', '2', '2000')
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> >>> s
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> ('a', 'ab', 'acd', 'bcd', '1a', 'a1', '222 bb', 'b a 4')
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>
>
> >>> sorted(n)
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> ['1', '10', '101', '13', '2', '2000', '3', '31', '40']
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> >>> sorted(s)
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> ['1a', '222 bb', 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd']
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> >>> sorted(n+s)
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> ['1', '10', '101', '13', '1a', '2', '2000', '222 bb', '3', '31', '40',
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> 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd']
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>
>
>
>
>
>
> Possibly there is a better way but for Python 2.7 this gives the
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> required result
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>
>
> Python 2.7.3 (default, Sep 26 2012, 21:51:14)
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>
>
> >>> sorted(int(x) if x.isdigit() else x for x in n+s)
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> [1, 2, 3, 10, 13, 31, 40, 101, 2000, '1a', '222 bb', 'a', 'a1', 'ab',
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> 'acd', 'b a 4', 'bcd']
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>
>
>
>
> [str(x) for x in sorted(int(x) if x.isdigit() else x for x in n+s)]
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> ['1', '2', '3', '10', '13', '31', '40', '101', '2000', '1a', '222 bb',
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> 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd']
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>
>
>
>
> But not for Python 3
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> Python 3.2.3 (default, Oct 19 2012, 19:53:16)
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>
>
> >>> sorted(n+s)
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> ['1', '10', '101', '13', '1a', '2', '2000', '222 bb', '3', '31', '40',
>
> 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd']
>
>
>
> >>> sorted(int(x) if x.isdigit() else x for x in n+s)
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> Traceback (most recent call last):
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> File "<stdin>", line 1, in <module>
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> TypeError: unorderable types: str() < int()
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> >>>
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>
>
> The best I can think of is to split the input sequence into two lists,
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> sort each and then join them.
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>
>
>
>
> --
>
> djc
>>> # Py 3.2.3
>>> z = ['1', '10', '101', '13', '1a', '2', '2000',
... '222 bb', '3', '31', '40', 'a', 'a1', 'ab',
... 'acd', 'b a 4', 'bcd'
... ]
>>> n, s = [], []
>>> for e in z:
... if e.isdigit():
... n.append(int(e))
... else:
... s.append(e)
...
>>> n.sort()
>>> s.sort()
>>> ns = [str(e) for e in n]
>>> ns.extend(s)
>>> ns
['1', '2', '3', '10', '13', '31', '40', '101', '2000', '1a',
'222 bb', 'a', 'a1', 'ab', 'acd', 'b a 4', 'bcd']
jmf
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