On Thu, Oct 25, 2012 at 12:02 AM, inshu chauhan <insidesh...@gmail.com> wrote: > I changed the programme to this : > def addtwice(self, x): > self.add(x) > self.add(x) > return x > y = Bag() > print y.addtwice(4) > > Now its not showing any error but result is same as the number passed for > adding twice ....
Do you understand how function calls work? A function like "y.addtwice" is called with an argument of 4, and the return value from the function is the value of the expression. some_value = y.addtwice(4) print some_value Take the return value and put it in the place where the function call was. In this case, the return value is x, the number you passed in as an argument. What exactly do you expect addtwice to return? Should it return the bag object (self)? Should it return True to say that it's been added successfully (or False if there's an error)? Should it return the number of items in the bag? Should it return 0 for success and a nonzero error code for failure? Should it always return None, throwing an exception if anything goes wrong? All of these make sense, you just have to choose which one you want. (I'm handwaving away a lot of complexity here, like un/bound methods and member lookups. Bear with me. I'm also ignoring the fact that some things just aren't Pythonic. The bear isn't complaining about that, so nor should you.) ChrisA -- http://mail.python.org/mailman/listinfo/python-list
