ok I got it guys... On Tue, Oct 23, 2012 at 10:08 PM, Joshua Landau <joshua.landau...@gmail.com>wrote:
> On 23 October 2012 21:06, Joshua Landau <joshua.landau...@gmail.com>wrote: > >> On 23 October 2012 21:03, Joshua Landau <joshua.landau...@gmail.com>wrote: >> >>> On 23 October 2012 12:07, Jean-Michel Pichavant >>> <jeanmic...@sequans.com>wrote: >>> >>>> ----- Original Message ----- >>>> >>>> > Thankyou.. but my problem is different than simply joining 2 lists >>>> > and it is done now :).... >>>> >>>> >>>> A lot of people though you were asking for joining lists, you >>>> description was misleading. >>>> >>>> I'll take a guess: you want to flatten a list of list. >>>> "Nested" list comprehensions can do the trick. >>>> >>>> aList =[[1,5], [2,'a']] >>>> [item for sublist in aList for item in sublist] >>>> >>>> ... >>>> [1, 5, 2, 'a'] >>>> >>>> I find it rather difficult to read though. >>> >>> >>> We have a library function for this, in the one-and-only itertools. >>> >>> >>> listoflists = [list(range(x, 2*x)) for x in range(5)] >>>> >>> listoflists >>>> [[], [1], [2, 3], [3, 4, 5], [4, 5, 6, 7]] >>>> >>> from itertools import chain >>>> >>> list(chain.from_iterable(listoflists)) >>>> [1, 2, 3, 3, 4, 5, 4, 5, 6, 7] >>> >>> >>> It does exactly what it says... fast and easy-to-read. >> >> >> Note that I think what he really wanted is to go from >> >> a, b, c = [list(x) for x in (range(10), range(11, 20), range(21, 30))] >> >> to >> >>> list(range(30)) >> >> > UNDO! UNDO! UNDO! > > I *meant *to say: > > Note that I think what he really wanted is to go from > > a, b, c = [list(x) for x in (range(10), range(11, 20), range(21, 30))] > > to > >> [a, b, c] > >
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