Tharanga Abeyseela <tharanga.abeyse...@gmail.com> writes: > I need to remove the parent node, if a particular match found.
It looks like you can't get the parent of an Element with elementtree (I would love to be proven wrong on this). The solution is to find all nodes that have a Rating (grand-) child, and then test explicitly for the value you're looking for. > <?xml version="1.0" encoding="ISO-8859-1" standalone="yes"?> > <Feed xmlns="http://schemas.xxxx.xx/xx/2011/06/13/xx";> > <TVEpisode> [...] > <ParentalControl> > <System>xxxx</System> > <Rating>M</Rating> > for child in > root.findall(".//{http://schemas.CCC.com/CCC/2011/06/13/CC}Rating";): > x = child.find('Rating').text > if child[1].text == 'NC': > print "found" > root.remove('TVEpisode') ????? Your code doesn't work because findall() already returns Rating elements, and these have no Rating child (so your first call to find() fails, i.e., returns None). And list indexes starts at 0, btw. Also, Rating is not a child of TVEpisode, it is a child of ParentalControl. Here is my suggestion: # Find nodes having a ParentalControl child for child in root.findall(".//*[ParentalControl]"): x = child.find("ParentalControl/Rating").text if x == "NC": ... Note that a complete XPath implementation would make that simpler: your query basically is //*[ParentalControl/Rating=="NC"] -- Alain. -- http://mail.python.org/mailman/listinfo/python-list
