Marco Nawijn, 16.10.2012 12:17: > On Tuesday, October 16, 2012 10:11:52 AM UTC+2, aaron.l...@gmail.com wrote: >> I have a C++ module where I have a defined, working type. How would I >> make a wrapper for this type to be able to be used in Python? I am >> familiar(-ish) with the C-API for functions but I can't see concretely how >> one would include an interface to a type. >> >> Is it this? http://docs.python.org/release/2.7.3/extending/newtypes.html > > There are a few ways of doing this. At least three come to my mind: > 1. Wrap the C++ type yourself by using handcrafted code implemented with the > Python C API > 2. Use SWIG to wrap the C++ code and (semi) automatically create the wrapper > (http://www.swig.org/) > 3. Use BOOST Python to wrap the C++ code > (http://www.boost.org/doc/libs/1_51_0/libs/python/doc/index.html) > > I would highly discourage (1) unless you are very brave and curious. Ofcourse > it is a nice excercise, but if you want something to work quickly I would > recommend to use either (2) or (3). > > I have used both SWIG and BOOST Python and either of them worked pretty well > for me. In the end I selected BOOST Python, because I was only interested in > the Python wrapping (SWIG could generate many other wrappers as well).
There's also Cython, which provides a very flexible way (unlike SWIG) of doing these things easily (unlike C++ with Boost). http://docs.cython.org/src/userguide/wrapping_CPlusPlus.html I agree with discouraging 1) in specific. Stefan -- http://mail.python.org/mailman/listinfo/python-list
