x3=re.match("\s{6}+",str)
instead use
x3=re.match("\s{6,}",str)
This serves the purpose. And also give some food for thought for why the first
one throws an error.
Cheers,
Saroo
-----Original Message-----
From: Python-list
[mailto:python-list-bounces+saroo_jain=infosys....@python.org] On Behalf Of
Mark Lawrence
Sent: Friday, October 05, 2012 3:29 AM
To: python-list@python.org
Subject: Re: + in regular expression
On 04/10/2012 04:01, contro opinion wrote:
>>>> str=" gg"
>>>> x1=re.match("\s+",str)
>>>> x1
> <_sre.SRE_Match object at 0xb7354db0>
>>>> x2=re.match("\s{6}",str)
>>>> x2
> <_sre.SRE_Match object at 0xb7337f38>
>>>> x3=re.match("\s{6}+",str)
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> File "/usr/lib/python2.6/re.py", line 137, in match
> return _compile(pattern, flags).match(string)
> File "/usr/lib/python2.6/re.py", line 245, in _compile
> raise error, v # invalid expression
> sre_constants.error: multiple repeat
>>>>
>
> why the "\s{6}+" is not a regular pattern?
>
>
>
Why are you too lazy to do any research before posting a question?
--
Cheers.
Mark Lawrence.
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