Paul Rubin於 2012年9月27日星期四UTC+8上午5時43分58秒寫道： > TP <t...@frenoespam.fr.invalid> writes: > > > copies a list, he copies in fact the *pointer* to the list .... > > > Is it the correct explanation? > > > > Yes, that is correct. > > > > > In these conditions, how to make this list [[0,0,0],[0,0,0]] with "*" > > > without this behavior? > > > > >>> a = [[0]*3 for i in xrange(2)] > > >>> a[0][0]=2 > > >>> a > > [[2, 0, 0], [0, 0, 0]]
I used numpy before. Python is not lisp but python can emulate the lisp behaviors. -- http://mail.python.org/mailman/listinfo/python-list
