f = open( '../' + page.pop() ) 15.09.2012 17:32 пользователь "Νικόλαος Κούρας" <nikos.gr...@gmail.com> написал:
> Τη Σάββατο, 15 Σεπτεμβρίου 2012 3:34:34 μ.μ. UTC+3, ο χρήστης Chris > Angelico έγραψε: > > On Sat, Sep 15, 2012 at 10:22 PM, Νικόλαος Κούρας <nikos.gr...@gmail.com> > wrote: > > > > > Hello, > > > > > > > > > > I recently changed webhost and in the new one iam getting this error > you can see if you visit http://superhost.gr when program execution > reaches the line: > > > > > > > > > > f = open( '../' + page ) > > > > > > > > > > In the previous host i wasn't getting this error. > > > > > > > > > > page's contents is: > > > > > > > > > > page = form.getvalue('page') > > > > > > > > Well, clearly '../' is a string (str), and page must be a list. But > > > > without knowing your web framework it's hard to be sure what's going > > > > on. > > > > > > > > My guess is that form.getvalue() is returning a list of form elements > > > > with that name, so you have a list with one element in it. But check > > > > your documentation to be sure. > > > > > > > > Since this changed when you changed hosts, it may mean you now have a > > > > completely different framework. Possibly you can configure this. > > > > Alternatively, it may simply be a different version of the same > > > > system. It's hard to know just based on this, though. > > > > > > > > ChrisA > > Iam not using frameworks just plain python code written in Notepad++ > > Can you please tell me how to switch this line in order for this line to > work? > -- > http://mail.python.org/mailman/listinfo/python-list >
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