On Tuesday, 28 August 2012 23:49:54 UTC+1, MRAB wrote: > On 28/08/2012 23:34, 9bizy wrote: > > > This is what I have to reproduce the challenge I am having below: > > > > > > > > > import csv > > > import struct > > > > > > > > > data = [] > > > > > > for Node in csv.reader(file('s_data.xls')): > > > > That tries to read the file as CSV, but, judging from the extension, > > it's in Excel's format. You don't even use what is read, i.e. Node. > > > > > data.append(list((file('s_data.xls')))) > > > > > That opens the file again and 'list' causes it to read the file as > > though it were a series of lines in a text file, which, as I've said, > > it looks like it isn't. The list of 'lines' is appended to the list > > 'data', so that's a list of lists. > > > > > > data = struct.unpack('!B4HH', data) > > > print "s_data.csv: ", data > > > > > > I tries so many format for the struct.unpack but I got this errors: > > > > > > Traceback (most recent call last): > > > > > > data = struct.unpack('!B4HH', data) > > > struct.error: unpack requires a string argument of length 11 > > > > > [snip] > > It's complaining because it's expecting a string argument but you're > > giving it a list instead.
How do I then convert data to a string argument in this case? -- http://mail.python.org/mailman/listinfo/python-list