On 23/08/2012 10:05, Mark Carter wrote:
Suppose I want to define a function "safe", which returns the argument passed if there is no error, and 42 if there is one. So the setup is something like:def safe(x): # WHAT WOULD DEFINE HERE? print safe(666) # prints 666 print safe(1/0) # prints 42 I don't see how such a function could be defined. Is it possible?
Well you've already got lots of answers but I'm not certain about what you're trying to achieve. If you could explicitly state your requirements I'm sure that the numerous MVPs (Most Valuable Pythonistas) here would come up with The Best Solution ™ to your problem.
-- Cheers. Mark Lawrence. -- http://mail.python.org/mailman/listinfo/python-list
