On Aug 18, 12:22 pm, Jussi Piitulainen <jpiit...@ling.helsinki.fi>
wrote:
> Frank Koshti writes:
> > not always placed in HTML, and even in HTML, they may appear in
> > strange places, such as <h1 $foo(x=3)>Hello</h1>. My specific issue
> > is I need to match, process and replace $foo(x=3), knowing that
> > (x=3) is optional, and the token might appear simply as $foo.
>
> > To do this, I decided to use:
>
> > re.compile('\$\w*\(?.*?\)').findall(mystring)
>
> > the issue with this is it doesn't match $foo by itself, and requires
> > there to be () at the end.
>
> Adding a ? after the meant-to-be-optional expression would let the
> regex engine know what you want. You can also separate the mandatory
> and the optional part in the regex to receive pairs as matches. The
> test program below prints this:
>
> >$foo()$foo(bar=3)$$$foo($)$foo($bar(v=0))etc</htm
>
> ('$foo', '')
> ('$foo', '(bar=3)')
> ('$foo', '($)')
> ('$foo', '')
> ('$bar', '(v=0)')
>
> Here is the program:
>
> import re
>
> def grab(text):
> p = re.compile(r'([$]\w+)([(][^()]+[)])?')
> return re.findall(p, text)
>
> def test(html):
> print(html)
> for hit in grab(html):
> print(hit)
>
> if __name__ == '__main__':
> test('>$foo()$foo(bar=3)$$$foo($)$foo($bar(v=0))etc</htm')
You read my mind. I didn't even know that's possible. Thank you-
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