Terry Hancock wrote: > On Saturday 18 June 2005 02:05 am, John Machin wrote: > >>Doug Schwarz wrote: >> >>>In article <[EMAIL PROTECTED]>, >>> Leif K-Brooks <[EMAIL PROTECTED]> wrote: >>> >>>>How do I make a regular expression which will match the same character >>>>repeated one or more times, >>> >>>How's this? >>> >>> >>> [x[0] for x in re.findall(r'((.)\2*)', 'abbcccddddcccbba')] >>> ['a', 'bb', 'ccc', 'dddd', 'ccc', 'bb', 'a'] >> >>I think it's fantastic, but I'd be bound to say that given that it's the >>same as what I posted almost two days ago :-) > > > Guess there's only one obvious way to do it, then. ;-) >
Yep ... but probably a zillion ways in re.compile(r"perl", re.I).match(other_languages) -- http://mail.python.org/mailman/listinfo/python-list
