On Wed, Jul 11, 2012 at 4:28 AM, Colin J. Williams <c...@ncf.ca> wrote: > I don't understand why you would expect 1, 2, 4.
Because: funcs[0](2) == 2 ** 0 == 1 funcs[1](2) == 2 ** 1 == 2 funcs[2](2) == 2 ** 2 == 4 > Perhaps parentheses will help the order of evaluation: > > funcs = [(lambda x: x**i) for i in range( 5 )] > > This gives: > 1 > 16 > 81 No, that gives 16, 16, 16 just like the original. I don't understand why you would expect 1, 16, 81, unless you have misread the code. -- http://mail.python.org/mailman/listinfo/python-list
