If you do want an in-place extension, you could try: aList=[1,2,3,4,5,6,7,8,9,10] xList=[1,2,3] print "The concatenated lists are:", aList + bList
Though you need to remember that neither aList nor bList is altered in this situation! Matthew Lefavor NASA GSFC [Microtel, LLC] Mail Code 699.0/Org Code 582.0 matthew.lefa...@nasa.gov (301) 614-6818 (Desk) (443) 758-4891 (Cell) From: levi nie <levinie...@gmail.com> To: "python-list@python.org" <python-list@python.org> Subject: Re: something go wrongly Thanks, Such methods return None to emphasize that they do not create new lists. i got it. 2012/7/8 Chris Rebert <c...@rebertia.com> On Sat, Jul 7, 2012 at 10:23 AM, levi nie <levinie...@gmail.com> wrote: > my code: > > aList=[1,2,3,4,5,6,7,8,9,10] > xList=[1,2,3] > print "now aList is",aList.extend(xList) > > output: > now aList is None > > what i want is [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 1, 2, 3] See http://stackoverflow.com/a/1682601 list.extend(), list.append(), etc. operate in-place, mutating the existing list object. Such methods return None to emphasize that they do not create new lists. Regards, Chris -- http://mail.python.org/mailman/listinfo/python-list
