in the code2
aList=[1,2,3,4,5,6,7,8,9,10]
aList=str(aList) #<--- here you convert the list in a string
print aList
print aList[2] #<-- here you are printing the third caracter of the
string '[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]' not the list '[1, 2, 3, 4, 5,
6, 7, 8, 9, 10]'
regards
Matteo
Il 04/07/2012 09:28, levi nie ha scritto:
Hi,Harrison.
Your method is cool.
But i doubt this, if bList and aList just are attached to the same
List when i write bList=aList,but why the output of the following two
code are different?
code1:
aList=[1,2,3,4,5,6,7,8,9,10]
bList=aList
bList=str(bList)
print aList
print aList[2]
code2:
aList=[1,2,3,4,5,6,7,8,9,10]
aList=str(aList)
print aList
print aList[2]
i'm puzzled now.
2012/7/4 Harrison Morgan <harrison.mor...@gmail.com
<mailto:harrison.mor...@gmail.com>>
On Wed, Jul 4, 2012 at 12:38 AM, levi nie <levinie...@gmail.com
<mailto:levinie...@gmail.com>> wrote:
that's good,thanks.
new problem.
when i write
bList=aList
del bList[2]
bList and aList both change,how can i make aList not changed?
Lists are mutable. That means that when you do bList = aList,
you're just creating another reference to aList. They both point
to the same list, just using different names. You should read up a
bit on immutable vs. mutable objects. Here's something that I
found that might explain it a bit better.
http://henry.precheur.org/python/copy_list
