Thanks Andrew and Michael!. That did the trick.
def get_numbers(first_num, second_num, operator):
if operator == 'add':
value = first_num + second_num
elif operator == 'minus':
value = first_num - second_num
elif operator == 'divide':
value = first_num / second_num
elif operator == 'multiply':
value = first_num * second_num
return value
print "%r" % (get_numbers(1, 2, 'minus'))
print "%r" % (get_numbers(1+3, 2+9, 'add'))
print "%r" % (get_numbers(10, 2, 'divide'))
output:
-1
15
5
On Fri, Jun 22, 2012 at 12:23 PM, Andrew Berg <bahamutzero8...@gmail.com>wrote:
> On 6/21/2012 10:42 PM, Xander Solis wrote:
> > Hello Python list,
> >
> > Noob here with a newbie question. I'm reading and working on the
> > exercise of the book, Learn Python the Hard way 2.0. When I use this
> > code, I get "None" on the output. My question is why does this happen?
> Your function prints the number and then returns None (you have no
> return statement in the function to change this) to the print statement.
> If you want to have the function return a value, use the return
> statement instead of print inside the function:
>
> def func(some_value):
> return some_value
> x = func(5)
> print x
>
> will print 5.
>
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