Answer in this topic should help you to solve issue. http://stackoverflow.com/questions/8152161/open-persian-url-domains-with-urllib2?answertab=active#tab-top
Regards. 2012/6/13 John Nagle <na...@animats.com> > I'm trying to open > > http://пример.испытание <http://xn--e1afmkfd.xn--80akhbyknj4f> > > with > > urllib2.urlopen(s1) > > in Python 2.7 on Windows 7. This produces a Unicode exception: > > >>> s1 > u'http://\u043f\u0440\u0438\**u043c\u0435\u0440.\u0438\** > u0441\u043f\u044b\u0442\u0430\**u043d\u0438\u0435' > >>> fd = urllib2.urlopen(s1) > Traceback (most recent call last): > File "<stdin>", line 1, in <module> > File "C:\python27\lib\urllib2.py", line 126, in urlopen > return _opener.open(url, data, timeout) > File "C:\python27\lib\urllib2.py", line 394, in open > response = self._open(req, data) > File "C:\python27\lib\urllib2.py", line 412, in _open > '_open', req) > File "C:\python27\lib\urllib2.py", line 372, in _call_chain > result = func(*args) > File "C:\python27\lib\urllib2.py", line 1199, in http_open > return self.do_open(httplib.**HTTPConnection, req) > File "C:\python27\lib\urllib2.py", line 1168, in do_open > h.request(req.get_method(), req.get_selector(), req.data, headers) > File "C:\python27\lib\httplib.py", line 955, in request > self._send_request(method, url, body, headers) > File "C:\python27\lib\httplib.py", line 988, in _send_request > self.putheader(hdr, value) > File "C:\python27\lib\httplib.py", line 935, in putheader > hdr = '%s: %s' % (header, '\r\n\t'.join([str(v) for v in values])) > UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-5: > ordinal not in range(128) > >>> > > The HTTP library is trying to put the URL in the header as ASCII. Why > isn't "urllib2" handling that? > > What does "urllib2" want? Percent escapes? Punycode? > > John Nagle > -- > http://mail.python.org/**mailman/listinfo/python-list<http://mail.python.org/mailman/listinfo/python-list> >
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