On 06/06/2012 03:00, Dave Angel wrote:
On 06/05/2012 09:43 PM, Miriam Gomez Rios wrote:
Hello, I think that the example in section 4.4 in the tutorial for python 2.7X
is wrong.
http://docs.python.org/tutorial/controlflow.html
It will end up printing this if you run the exact code listed in the tutorial.
3 is a prime number
4 equals 2*2
5 is a prime number
5 is a prime number
5 is a prime number
6 equals 2 * 3
7 is a prime number
7 is a prime number
7 is a prime number
7 is a prime number
7 is a prime number
8 equals 2*4
9 is a prime number
9 equals 3*3
I believe it is because the is no break in " else print n is a prime number"
and
it never prints anything about number 2 because the second for is like
range(2,2)
which is empty so it does nothing.
Hate to tell you, but the example works as it exists on the website. If
you got your output, you must have messed up the indentation, which is
VERY important in python.
In particular, the else clause has to line up with the for statement,
NOT with the if statement.
If it helps, this is the correct indentation. Paste it into a file, and
run it.
for n in range(2, 10):
for x in range(2, n):
if n % x == 0:
print n, 'equals', x, '*', n/x
break
else:
# loop fell through without finding a factor
print n, 'is a prime number'
I can confirm that the OP's output is what you get when the 'else' is
indented the same as the 'if'.
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