I am confused by some of the dictionary setdefault behaviour, I think
I am probably missing the obvious here.
def someOtherFunct():
print "in someOtherFunct"
return 42
def someFunct():
myDict = {1: 2}
if myDict.has_key(1):
print "myDict has key 1"
x = myDict.setdefault(1, someOtherFunct()) # <<<<< I didn't
expect someOtherFunct to get called here
print "x", x
y = myDict.setdefault(5, someOtherFunct())
print "y", y
+++++++++++++++++++++
if I call someFunct() I get the following output
myDict has key 1
in someOtherFunct
x 2
in someOtherFunct
y 42
For the second use of setdefault I do expect a call as the dictionary
does not the key. Will the function, someOtherFunct, in setdefault
always be called anyway and it is just that the dictionary will not be
updated in any way?
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