Thanks Dave and Shashank . I cleared the concept also. I got it guys. In my piece of code where i was doing this
In [25]: [k for k,v in for_patient_type.iteritems() if v == "Real"] Out[25]: [80, 81, 83, 84, 91, 93, 79] thats what shashank suggest later. Thanks to you Dave.I cleared my concept which i just forgot. On Tue, Apr 10, 2012 at 12:54 PM, Shashank Singh < shashank.sunny.si...@gmail.com> wrote: > > > On Tue, Apr 10, 2012 at 12:16 AM, Dave Angel <d...@davea.name> wrote: > >> On 04/10/2012 02:04 AM, Shashank Singh wrote: >> > On Mon, Apr 9, 2012 at 10:49 PM, Nikhil Verma <varma.nikhi...@gmail.com >> >wrote: >> > <SNIP> >> >> I am trying this but its giving me a generator object. >> >> >> >> In [9]: (k for k,v in for_patient_type.iteritems() if v == 'Real') >> >> >> > Iterating over a dict gives you all the keys, not the key value pairs >> > >> >> But that line does not iterate over the dict, it iterates over an >> iterator consisting of key/value pairs. Note he had a call to >> iteritems(). >> > > Thanks Dave. > My bad. Nikhil, you could get the data that you wanted by your initial > approach. All you needed was to either run through the generator or just > use list comprehension > > >>> g = (k for k,v in for_patient_type.iteritems() if v == 'Real') > >>> for k in g: print k > ... > 80 > 81 > 83 > 84 > 91 > 93 > 79 > >>> > > > >>> [k for k,v in for_patient_type.iteritems() if v == 'Real'] > [80, 81, 83, 84, 91, 93, 79] > > > -- > Regards > Shashank Singh > http://www.flipora.com > http://r <http://www.cse.iitb.ac.in/%7Eshashanksingh> > ationalpie.wordpress.com > > -- Regards Nikhil Verma +91-958-273-3156
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