Maarten wrote: > Alternatively you can figure out the parent class with a call to super:
This is WRONG: > super(self.__class__, self).__init__() You have to name the current class explicitly. Consider: >> class A(object): ... def __init__(self): ... print "in a" ... >>> class B(A): ... def __init__(self): ... print "in b" ... super(self.__class__, self).__init__() # wrong ... >>> class C(B): pass ... >>> Can you figure out what C() will print? Try it out if you can't. The corrected code: >>> class B(A): ... def __init__(self): ... print "in b" ... super(B, self).__init__() ... >>> class C(B): pass ... >>> C() in b in a <__main__.C object at 0x7fcfafd52b10> In Python 3 you can call super() with no args; super().__init__() do the right thing there. -- http://mail.python.org/mailman/listinfo/python-list
