On 16 February 2012 05:03, Ian Kelly <ian.g.ke...@gmail.com> wrote:
> On Wed, Feb 15, 2012 at 6:11 PM, HoneyMonster <someone@someplace.invalid>
> wrote:
>> As to your first suggestion though, I am having some difficulty. Note
>> that the vulnerability rotates; i.e. CONDITIONS[4] is not the same as
>> CONDITIONS[0].
>> Is there a better way of doing it than a simple list.append()?
>
> Ah, it's more complicated than I realized. I believe this generates
> the correct result, although adding None to the dealers list is
> somewhat unsatisfactory:
>
> DEALERS = ["Dealer North", "Dealer East", "Dealer South", "Dealer West", None]
> VULNERABILITIES = [
> "Neither vulnerable", "North-South vulnerable",
> "East-West vulnerable", "Both vulnerable",
> ]
> CONDITIONS = [(d, v) for (d, v) in zip(DEALERS * 4, VULNERABILITIES * 5) if d]
You could also do:
DEALERS = ["Dealer North", "Dealer East", "Dealer South", "Dealer West"]
VULNERABILITIES = [
"Neither vulnerable", "North-South vulnerable",
"East-West vulnerable", "Both vulnerable",
]
CONDITIONS = [
(DEALERS[j], VULNERABILITIES[(i + j)%4])
for i in range(4) for j in range(4)
]
If you don't care about the order in which the conditions are listed,
you could use
CONDITIONS = itertools.product(DEALERS, VULNERABILITIES)
(But maybe you do, I haven't looked at the code)
--
Arnaud
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