On Feb 10, 7:52 pm, 7stud <7s...@excite.com> wrote:
I don't know if this helps, but I notice when I initially do this:
shelve.open('data22')
the file is saved as 'data22.db'. But on subsequent calls to
shelve.open(), if I use the file name 'data22.db', I get a different
error:
--output:--
**** defaultdict(<class 'int'>, {'Joe': 30})
Traceback (most recent call last):
File "3.py", line 95, in <module>
d.load()
File "3.py", line 86, in load
my_shelve = shelve.open('data22.db')
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/
python3.2/shelve.py", line 232, in open
return DbfilenameShelf(filename, flag, protocol, writeback)
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/
python3.2/shelve.py", line 216, in __init__
Shelf.__init__(self, dbm.open(filename, flag), protocol,
writeback)
File "/Library/Frameworks/Python.framework/Versions/3.2/lib/
python3.2/dbm/__init__.py", line 83, in open
raise error[0]("db type could not be determined")
dbm.error: db type could not be determined
The code that produced that error:
import collections as c
import shelve
class Dog(c.defaultdict):
def __init__(self):
super().__init__(int, Joe=30)
print('****', self)
def save(self):
my_shelve = shelve.open('data22')
my_shelve['dd'] = self
my_shelve.close()
def load(self):
my_shelve = shelve.open('data22.db')
data = my_shelve['dd']
my_shelve.close()
print(data)
d = Dog()
d.save()
d.load()
I'm using python 3.2.2.
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