I'm guessing you meant for this to be on-list, and am hoping you don't mind that I'm replying on-list.
On Sat, Dec 24, 2011 at 8:16 AM, Gnarlodious <gnarlodi...@gmail.com> wrote: > Chris Angelico wrote: >> [(m, os.path.getmtime(m)) for m in (imp.find_module(module)[1] for >> module in modules)] >> >> Yeah, a little hard to read. Tell me, does this formulation execute >> imp.find_module(module) once or twice for each modname? What this does is save a temporary list, more or less. (It's actually a generator expression, not a list comprehension, but that's immaterial.) temporary = [imp.find_module(module)[1] for module in modules] [(m, os.path.getmtime(m)) for m in temporary] It iterates over modules, calling find_module for each, and saving the results to a new list. Then separately iterates over the new list, pairing each with the getmtime. Since I used parentheses instead of square brackets in the original expression, Python won't actually build the full list. Other than that, it's equivalent to the two-statement version, and you can try those two in IDLE to see what they do. ChrisA -- http://mail.python.org/mailman/listinfo/python-list
