Re: Transform two tuples item by item

[Tim Chase]

On 12/19/11 20:04, Gnarlodious wrote:
What is the best way to operate on a tuple of values
transforming them against a tuple of operations? Result can be
a list or tuple:
tup=(35, '34', 0, 1, 31, 0, '既濟')

from cgi import escape
[tup[0], "<span> class='H'>{}</span>".format(tup[1]), bool(tup[2]),
bool(tup[3]), tup[4], bool(tup[5]), escape(tup[6])]

->  [35, "<span class='H'>34</span>", False, True, 31, False,
'&amp;#26082;&amp;#28639;']

But I want to loop rather than subscripting.

Well, you can do something like

>>> from cgi import escape
>>> nop = lambda x: x
>>> tup = (35, '34', 0, 1, 31, 0, '&#26082;&#28639;')
>>> ops = [nop, "<span class='H'>{0}</span>".format, bool, bool, 
nop, bool, escape]
>>> [f(x) for f, x in zip(ops,tup)]
[35, "<span class='H'>34</span>", False, True, 31, False, 
'&amp;#26082;&amp;#28639;']

Note #1: I had to change your format from "{}" to "{0}", at least 
in 2.6 I've got here)

Note #2: it's spelled ".format" not ".format()" which puts the 
function reference in the "ops" list, not the results of calling it.

-tkc



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