Tim wrote:
> Hi, I need to generate a list of file names that increment, like this:
> fname1
> fname2
> fname3 and so on.
>
> I don't know how many I'll need until runtime so I figure a generator is
> called for.
>
> def fname_gen(stem):
> i = 0
> while True:
> i = i+1
> yield '%s%d' % (stem,i)
>
> blarg = fname_gen('blarg')
> boo = fname_gen('boo')
>
> n = 3
> for w in range(0,n):
> in_name = blarg.next()
> out_name = boo.next()
>
>
> This works, but is it the 'normal' way to accomplish the task when you
> don't know 'n' until run-time? thanks,
As a fan of the itertools module I would spell it (untested)
from itertools import count, islice, izip
def fname_gen(stem):
return ("%s%d" % (stem, i) for i in count(1))
# ...
for in_name, out_name in islice(izip(blarg, boo), n):
#...
but your way is perfectly OK.
--
http://mail.python.org/mailman/listinfo/python-list
