Gnarlodious wrote:
What I say is this:
def SaveEvents(self,events):
try:
plistlib.writePlist(events, self.path+'/Data/Events.plist') #
None if OK
except IOError:
return "IOError: [Errno 13] Apache can't write Events.plist
file"
Note that success returns"None" while failure returns a string.
I catch the error like this:
errorStatus=Data.Dict.SaveEvents(Data.Plist.Events)
if errorStatus: content=errorStatus
It works, but isn there a more elegant way to do it? As in, one line?
I can imagine if success returned nothing then content would remain
unchanged. Isn't there a built-in way to send an error string back and
then catch it as a variable name?
This is Py3 inside WSGI.
-- Gnarlie
Hi,
There's no need to rephrase an exception unless you want to *add*
information.
def saveEvents(self,events):
plistlib.writePlist(events, self.path+'/Data/Events.plist')
try:
Data.Dict.SaveEvents(Data.Plist.Events)
except IOError, exc: # i'm using python 2.5, this except clause may have
changed in py3
content = str(exc)
JM
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