On 27/10/11 10:57:55, faucheuse wrote:
I'm trying to launch my python program with another process name than
"python.exe".
Which version of Python are you using?
Which version of which operating system?
In order to do that I'm trying to use the os.execvp function :
os.execvp("./Launch.py", ["ProcessName"])
Launch.py is the file that Launch the program and ProcessName is
the ... Process Name ^^
I get this error : OSError : [Errno 8] Exec format error.
Maybe ./Lauch.py is not executable.....
Can you run ./Launch.py from the command line?
Does it have a valid shebang line?
Is the 'x' bit set?
What does "file ./Launch.py" report?
I searched and found many solutions like : os.execvp("./Launch.py",
["./Launch.py","ProcessName"]), but nothing worked so far.
This works for me:
os.execvp("./Launch.py", ["ProcessName"]])
-- HansM
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