On Sun, Sep 18, 2011 at 11:22 AM, Vincent Vande Vyvre <
vincent.vandevy...@swing.be> wrote:
> **
> Le 18/09/11 11:39, Kayode Odeyemi a écrit :
>
> items = {'fees':[('status','pending'), ('timeout',60)],
> 'hostel':[('status',
> 'pending'), ('timeout','120')]}
>
> Like that:
>
> # -*- coding: utf-8 -*-
>
>
> items = {'fees':[('status','pending'), ('timeout',60)],
> 'hostel':[('status',
> 'pending'), ('timeout','120')]}
>
> for key, value in items.iteritems():
> print "\n {0}".format(key)
> for val in value:
> print "\t{0}: {1}".format(val[0], val[1])
>
> for python 2.x
>
Vincent, with:
values = ('status', 'pending') ('timeout', '120') ('status', 'pending')
('timeout', 60)
How do I comma separate it and put each each item in a dict?
>>> for key, value in items.iteritems():
... for val in value:
... md = {}
... for q in val:
... md.update(q)
... print md
...
Traceback (most recent call last):
File "<stdin>", line 5, in <module>
ValueError: dictionary update sequence element #0 has length 1; 2 is
required
Thank you
--
Odeyemi 'Kayode O.
http://www.sinati.com. t: @charyorde
--
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