You probably want to look at using struct.pack. That will allow you
to back heterogenious groups of data into a string that can be saved
to disk or sent over the network. It also does a really good job of
taking care of byte order for you(if you tell it to).
-Chris
On 8 Jun 2005 10:40:43 -0700, [EMAIL PROTECTED] <[EMAIL PROTECTED]> wrote:
> How do i fill 1 byte and 4 bytes in a single array? This array contains
> packet information.
>
> Python code...
>
> from array import *
>
> size = 526
> pData = array("B", '\0'* 526)
> # Destination MAC address
> destAddress = FFFFFFFFFFFF
> for i in range(0, len(destAddress), 2):
> pData[i/2] = int(destAddress[i:i+2], 16)
>
> pattern = 0xAAAAAAAA
> for i in range( 512):
> pData[i+6] = long(pattern, 16)
> print pData
>
> OverflowError: long int too large to covert to int
>
> def test(pData.buffer_info()[0])
> ....
> ....
> Any help appreciated.
> -Ashton
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
--
Christopher Lambacher
[EMAIL PROTECTED]
--
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