-----Original Message----- From: python-list-bounces+ramit.prasad=jpmorgan....@python.org [mailto:python-list-bounces+ramit.prasad=jpmorgan....@python.org] On Behalf Of Antonio Vera Sent: Tuesday, August 09, 2011 12:02 PM To: python-list@python.org Subject: Passing every element of a list as argument to a function
Hi!, I have a very simple syntax question. I want to evaluate a library function f receiving an arbitrary number of arguments (like itertools.product), on the elements of a list l. This means that I want to compute f(l[0],l[1],...,l[len(l)-1]). Is there any operation "op" such that f(op(l)) will give the sequence of elements of l as arguments to f? Thanks for your time. Best, Antonio -- http://mail.python.org/mailman/listinfo/python-list op(*l) for a list (or positional arguments). If you are trying to pass named keyword arguments then you must pass it a dictionary { 'keywordName' : 'value' } Example: >>>def F(name=None): pass >>>F(**{'name':'boo'}) Ramit Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology 712 Main Street | Houston, TX 77002 work phone: 713 - 216 - 5423 This email is confidential and subject to important disclaimers and conditions including on offers for the purchase or sale of securities, accuracy and completeness of information, viruses, confidentiality, legal privilege, and legal entity disclaimers, available at http://www.jpmorgan.com/pages/disclosures/email. -- http://mail.python.org/mailman/listinfo/python-list
