Sells, Fred wrote:
> I'm tring to unzip a buffer that is uploaded to django/python. I can
> unzip the file in batch mode just fine, but when I get the buffer I get
> a "BadZipfile exception. I wrote this snippet to try to isolate the
> issue but I don't understand what's going on. I'm guessing that I'm
> losing some header/trailer somewhere?
Why are you copying the file before you try to unzip it?
> def unittestZipfile(filename):
> buffer = ''
> f = open(filename)
Open the file in binary mode:
f = open(filename, "rb")
> for i in range(22):
> block = f.read()
> if len(block) == 0:
> break
> else:
> buffer += block
> print len(buffer)
> tmp = open('tmp.zip', 'w')
Again, open the file in binary mode ("wb").
> tmp.write(buffer)
> tmp.close()
Not essential to the problem you are encountering, but you want
shutil.copyfile(). Also, have a look at the shutil.copyfileobj()
implementation to learn how to properly copy a file in chunks of limited
size.
> zf = zipfile.ZipFile('tmp.zip')
> print dir(zf)
> for name in zf.namelist():
> print name
> print zf.read(name)
> ____________________________________________________________
> 2.6.6 (r266:84297, Aug 24 2010, 18:46:32) [MSC v.1500 32 bit (Intel)]
> Traceback (most recent call last):
> File
> "C:\all\projects\AccMDS30Server\mds30\app\uploaders\xmitzipfile.py",
> line 162, in <module>
> unittestZipfile('wk1live7.8to7.11.zip')
> File
> "C:\all\projects\AccMDS30Server\mds30\app\uploaders\xmitzipfile.py",
> line 146, in unittestZipfile
> print zf.read(name)
> File "C:\alltools\python26\lib\zipfile.py", line 837, in read
> return self.open(name, "r", pwd).read()
> File "C:\alltools\python26\lib\zipfile.py", line 867, in open
> raise BadZipfile, "Bad magic number for file header"
> zipfile.BadZipfile: Bad magic number for file header
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