On Wed, 20 Jul 2011 01:17 pm CM wrote:
> I have three items in a dict, like this:
>
> the_dict = {'a':1, 'b':2, 'c':3}
>
> but the vals could be anything. I want to configure something else
> based on the "winner" of such a dict, with these rules:
>
> 1. In this dict, if there is a UNIQUE max value, that's the winner.
> 2. If there are any TIES for max value, b is the winner by default.
>
> The problem for me, as I see it, is I don't know any elegant ways to
> do this in Python. The max(dict) function doesn't distinguish between
> unique and non-unique maxes. I could go through and test the various
> possibilities (to see if the max value had any matches in the other
> values), but, knowing Python, there is probably something close to
> "one way to do it". Any suggestions?
# Untested.
def get_winner(adict):
values = sorted(adict.values(), reverse=True)
if values[0] == values[1]:
return adict['b']
else:
return values[0]
Assumes that adict has at least two items. May be slow if it has millions of
items.
--
Steven
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