Reinhold, Thanks for your response in the previous thread. Yours is an interesting question. I haven't come up with a solution, but I did realize that in the previous problem, the source 'word' doesn't really need to stay intact... So perhaps a solution along these lines?
>>> for a in enumerate(wlist): ... if a[1] in vowels: ... vees.append(wlist.pop(a[0])) I don't know if it's possible to cram a 'pop' command into the single line solution though. I look forward to seeing other tricks to this end... :) -- http://mail.python.org/mailman/listinfo/python-list
