Gabriel wrote: > Well, the subject says it almost all: I'd like to write a small Vector > class for arbitrary-dimensional vectors. > > I am wondering what would be the most efficient and/or most elegant > way to compute the length of such a Vector? > > Right now, I've got > > def length(self): > # x.length() = || x || > total = 0.0 > for k in range(len(self._coords)): > d = self._coords[k] > total += d*d > return sqrt(total) > > However, that seems a bit awkward to me (at least in Python ;-) ). > > I know there is the reduce() function, but I can't seem to find a way > to apply that to the case here (at least, not without jumping through > too many hoops). > > I have also googled a bit, but found nothing really elegant.
>>> class Vector(object): ... def __init__(self, *coords): ... self._coords = coords ... def __abs__(self): ... return math.sqrt(sum(x*x for x in self._coords)) ... >>> import math >>> abs(Vector(1,1)) 1.4142135623730951 >>> abs(Vector(3,4)) 5.0 -- http://mail.python.org/mailman/listinfo/python-list
