Kushal Kumaran wrote:
> That's how it is able to give you the status. So, if you
> are using getstatusoutput, you will have only one instance of your
> command running.
My intent is to launch only one program instance, which will goes as daemon.
To avoid a second call I'd like rather to use Python than
==============================code=========================================
def start(self):
'''try to start aria2c as a daemon and return its handle to where it
can
proceed to issue commands'''
# aria2c is running, then don't try it again
if (chkout('ps -A |grep aria2c')[0] > 0):
try:
chkout(self.ARIA_CMD)
except:
raise SystemExit('aria2c is not working as deamon')
elif self.handle: return self.handle
# everything is good, it will return an handle
self.handle= \
xmlrpclib.ServerProxy('http://localhost:%s/rpc' %int(self.numport))
return self.handle
==============================code=========================================
Here I've named subprocess.getstatusoutput as chkout, I'm calling 2 more
programs to find whether there's a running instance of aria2c. I think it's
not nice, python libraries should get the matter done.
--
goto /dev/null
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