On 05/17/2011 03:05 AM, Andrew Berg wrote:
On 2011.05.16 02:26 AM, Karim wrote:
Use regular expression for bad HTLM or beautifulSoup (google it), below
a exemple to extract all html links:
linksList = re.findall('<a href=(.*?)>.*?</a>',htmlSource)
for link in linksList:
print link
I was afraid I might have to use regexes (mostly because I could never
understand them).
Even the BeautifulSoup website itself admits it's awful with Python 3 -
only the admittedly broken 3.1.0 will work with Python 3 at all.
ElementTree doesn't seem to have been updated in a long time, so I'll
assume it won't work with Python 3.
lxml looks promising, but it doesn't say anywhere whether it'll work on
Python 3 or not, which is puzzling since the latest release was only a
couple months ago.
Actually, if I'm going to use regex, I might as well try to implement
Versions* in Python.
Thanks for the answers!
*http://en.totalcmd.pl/download/wfx/net/Versions (original, made for
Total Commander) and
https://addons.mozilla.org/en-US/firefox/addon/versions-wfx_versions/
(clone implemented as a Firefox add-on; it's so wonderful, I even wrote
the docs for it!)
Andrew,
I wrote a class with HMLTParser to get only one link for a given
project, cf below:
73 class ResultsLinkParser(HTMLParser.HTMLParser):
74 """Class ResultsLinkParser inherits form HTMLParser to extract
75 the original 'Submission date' of the a bug.
76 This customized parser will deals with the 'View Defect' HTML
77 page from Clear DDTS.
78 """
79 def __init__(self):
80 HTMLParser.HTMLParser.__init__(self)
81 self._link = None
82
83 def handle_starttag(self, tag, attrs):
84 """Implement standard class HTMLParser customizing method."""
85 if tag == 'frame':
86 try:
87 attributes = dict(attrs)
88 if attributes['name'] == 'indexframe':
89 self._link = attributes['src']
90 except KeyError, e:
91 print("""WARNING: Attribute '{keyname}' from frame tag
92 in QueryResult page does not
exist!""".format(keyname=e))
93
94 def link(self):
95 """Return the html link of the query results page."""
96 return self._link
You can use it and just modified it to get the latest just add some code
(and change the tag 'name' of my example) to compare revision number
with max and keep the max to compare it to the next value. I let you add
this little code just create self._revision = None in the __init__(self)
which hold the current max revision. After parser.feed() you can get the
value by parser._revision or a public parser.revision() method to get
the value.
Cheers
Karim
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