This piece of code works fine for me: > >>> somevar = bytes() > >>> somevar > '' > >>> somevar.replace(b'', b'10') > '10' > >>> somevar > '' > >>> somevar = somevar.replace(b'', b'10') > >>> somevar > '10' > >>> somevar2 = bytes(b'10'*2) > >>> somevar2 > '1010' > >>> somevar2 = somevar2.replace(b'01', b'57'*3) > >>> somevar2 > '15757570' > > They're unmutable, but replace deals with it. 2011/5/17 Ethan Furman <et...@stoneleaf.us>
> Felipe Bastos Nunes wrote: > > 2011/5/17 Ethan Furman wrote: >> >>> >>> In Python 3 one can say >>> >>> --> huh = bytes(5) >>> >>> Since the bytes type is actually a list of integers, I would have >>> expected this to have huh being a bytestring with one element -- the >>> integer 5. Actually, what you get is: >>> >>> --> huh >>> b'\x00\x00\x00\x00\x00' >>> >>> or five null bytes. Note that this is an immutable type, so you >>> cannot go in later and say >>> >>> --> huh[3] = 9 >>> Traceback (most recent call last): >>> File "<stdin>", line 1, in <module> >>> TypeError: 'bytes' object does not support item assignment >>> >>> >>> So, out of curiosity, does anyone actually use this, um, feature? >>> >> > > >> They accept .replace(b"00", b"12") for example. >> > > So they do. Although that particular example doesn't work since b'0' is > the integer 48... > > --> huh.replace(b'00',b'12') > > b'\x00\x00\x00\x00\x00' > > > The big question, though, is would you do it this way: > > some_var = bytes(23).replace(b'\x00', b'a') > > or this way? > > some_var = bytes(b'a' * 23) > > ~Ethan~ > -- Felipe Bastos Nunes
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