itertools can help you do this too:
import itertools
tl = [('0A',), ('1B',), ('2C',), ('3D',)]
itertools.chain.from_iterable(tl)
<itertools.chain object at 0x11f7ad0>
list(itertools.chain.from_iterable(tl))
['0A', '1B', '2C', '3D']
Checkout http://docs.python.org/library/itertools.html#itertools.chain
for more info.
On Mon, Apr 25, 2011 at 11:08 PM, Paul Rubin <no.email@nospam.invalid> wrote:
> Gnarlodious <gnarlodi...@gmail.com> writes:
>> I have an SQLite query that returns a list of tuples:
>> [('0A',), ('1B',), ('2C',), ('3D',),...
>> What is the most Pythonic way to loop through the list returning a
>> list like this?:
>> ['0A', '1B', '2C', '3D',...
>
> Try:
>
> tlist = [('0A',), ('1B',), ('2C',), ('3D',)]
> alist = [x for (x,) in tlist]
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