On 22/04/2011 15:57, Irmen de Jong wrote:
On 22-4-2011 15:55, Vlastimil Brom wrote:
Hi all,
I'd like to ask for comments or advice on a simple code for testing a
"subdict", i.e. check whether all items of a given dictionary are
present in a reference dictionary.
Sofar I have:
def is_subdict(test_dct, base_dct):
"""Test whether all the items of test_dct are present in base_dct."""
unique_obj = object()
for key, value in test_dct.items():
if not base_dct.get(key, unique_obj) == value:
return False
return True
I'd like to ask for possibly more idiomatic solutions, or more obvious
ways to do this. Did I maybe missed some builtin possibility?
I would use:
test_dct.items()<= base_dct.items()
In Python 2:
>>> test_dct = {"foo": 0, "bar": 1}
>>> base_dct = {"foo": 0, "bar": 1, "baz": 2}
>>>
>>> test_dct.items() <= base_dct.items()
False
In Python 3:
>>> test_dct = {"foo": 0, "bar": 1}
>>> base_dct = {"foo": 0, "bar": 1, "baz": 2}
>>> test_dct.items() <= base_dct.items()
True
YMMV
--
http://mail.python.org/mailman/listinfo/python-list
